factorise the. following 1-6x+9x^2
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Answered by
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take x term common and numeral terms coomon that= 6x+9x+1×2 which = 3x(2+3). (2).
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Hey friend , ✌✌
1 - 6x + 9x^2
==> First let's arrange the terms from highest power of x to lowest power
9x^2-6x+1 = 0
==> Now we must find the product of coefficient x square term and constant
9×1=9
==> Then we must find 2 numbers such that their product = 9 and sum = coefficient of x term = -6
9x^2 - 3x - 3x + 1 = 0 -----> -3-3=-6
-----> -3×-3=9
So they satisfy the condition
==> Now we must separate the two factors
3x ( 3x -1 ) - 1 ( 3x-1 )=0
(3x - 1)(3x - 1) =0
==> Now we must find x
3x - 1 = 0 ---> 3x = 1 ---> x = 1/3
==> 3x - 1 is a factor of the given equation
hope it helps pls mark as brainliest
1 - 6x + 9x^2
==> First let's arrange the terms from highest power of x to lowest power
9x^2-6x+1 = 0
==> Now we must find the product of coefficient x square term and constant
9×1=9
==> Then we must find 2 numbers such that their product = 9 and sum = coefficient of x term = -6
9x^2 - 3x - 3x + 1 = 0 -----> -3-3=-6
-----> -3×-3=9
So they satisfy the condition
==> Now we must separate the two factors
3x ( 3x -1 ) - 1 ( 3x-1 )=0
(3x - 1)(3x - 1) =0
==> Now we must find x
3x - 1 = 0 ---> 3x = 1 ---> x = 1/3
==> 3x - 1 is a factor of the given equation
hope it helps pls mark as brainliest
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