Question

factorise the. following 1-6x+9x^2

Answer 1

take x term common and numeral terms coomon that= 6x+9x+1×2 which = 3x(2+3). (2).

Answer 2

Hey friend , ✌✌

1 - 6x + 9x^2

==> First let's arrange the terms from highest power of x to lowest power

9x^2-6x+1 = 0

==> Now we must find the product of coefficient x square term and constant

9×1=9

==> Then we must find 2 numbers such that their product = 9 and sum = coefficient of x term = -6

9x^2 - 3x - 3x + 1 = 0 -----> -3-3=-6
-----> -3×-3=9

So they satisfy the condition

==> Now we must separate the two factors

3x ( 3x -1 ) - 1 ( 3x-1 )=0
(3x - 1)(3x - 1) =0

==> Now we must find x

3x - 1 = 0 ---> 3x = 1 ---> x = 1/3

==> 3x - 1 is a factor of the given equation

hope it helps pls mark as brainliest