Question

factorise the following
1. 6x²+9x+3
2. 5x²–13x–18​

Answer 1

1. ${6x}^{2} + 9x + 3 \\ {6x}^{2} + (6 + 3)x + 3 \\ {6x}^{2} + 6x + 3x + 3 \\ 6x(x + 1) + 3(x + 1) \\ (x + 1)(6x + 3) \: answer$

2. ${5x}^{2} - 13x - 18 \\ {5x}^{2} - (18 - 5)x - 18 \\ {5x}^{2} - 18x + 5x - 18 \\ {5x}^{2} + 5x - 18x - 18 \\ 5x(x + 1) - 18(x + 1) \\ (x + 1)(5x - 18) \: answer$

Answer 2

Solution:-

$6 {x}^{2} + 9x + 3 = 0 \\ 6 {x}^{2} + 6x + 3x + 3 = 0 \\ 6x(x + 1) + 3(x + 1) = 0 \\ (6x + 3)(x + 1) = 0 \\ x = \frac{ - 3}{6} (or) - 1$

• X = ${\Large{\red{\sf{\frac{-1}{2}}}}} \;(or)\;{\green{\bf{-1}}}$

Refer The Attachment ⬆️

• x = $\Large{\red{\sf{\frac{13±23}{10}}}}$

$\Large{✓}$

• MrMonarque ✨

Hope It Helps You ✌️