Question

factorise the following 1) a^2+2a+1

Answer 1

Answer:

(a+1) (a+1)

Step-by-step explanation:

In this question we will use mid term split method

a²+2a+1

=> a²+(1a+1a)+1

=> (a²+1a)+(1a+1)

=> a(a+1)+1(a+1)

=> (a+1)(a+1) ANSWER

hope it helps...thnku...pls like

Answer 2

Step-by-step explanation:

a²+2a+1=0

first multiply first and last term

1×1=1

so, we need to find the number whose sum is 2 and multiplication is 1

so the factors are 1 and 1

bcz 1×1=1

and 1+1=2

Now Substitute the factors

a²+1a+1a+1=0

a(a+1)+1(a+1)=0

Take common

(a+1) (a+1)=0

a+1=0 and a+1=0

a=-1 and a=-1 are the factors of the given quadratic equation