Question

factorise the following 1-(b-c)^2

Answer 1

1- (b-c)²
= 1²- (b-c)²
= (1-b+c)(1+b-c)

Answer 2

✌✌HERE IS YOUR ANSWER..⬇⬇

$\green{\underline{SOLUTION}}$ ➡

$1 - ( b- c) {}^{2} \\ \\ = (1) {}^{2} - (b - c) {}^{2} \\ \\ = (1 +b - c)(1 - b+ c) \: \: \: \: \: [using \: \: x {}^{2} - y {}^{2} = (x + y)(x - y) \: \: \: identy]$

✝✝$\green{\underline{.HOPE \: \: IT \: \:HELPS \: \: YOU.}}$✝✝