Question

factorise the following 12(2x-3y)^2-16(3y-2x)​

Answer 1

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(12 • ((2x - 3y)2)) - 16 • (3y - 2x)

STEP

2

:

Equation at the end of step 2

12 • (2x - 3y)2 - 16 • (3y - 2x)

STEP

3

:

Pulling out like terms

3.1 Pull out 3y-2x

Note that 2x-3y =(-1)• 3y-2x

After pulling out, we are left with :

(3y-2x) • ( 12 * (2x-3y) +( 16 * 1 ))

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

24x - 36y + 16 = 4 • (6x - 9y + 4)

Final result :

4 • (3y - 2x) • (6x - 9y + 4)

Answer 2

Answer:

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