Factorise the following : 12(a + b)2 – 5(a + b) – 3
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Answer:
8a3−b3−12a2b+6ab2
=(2a)3+(−b)3+3(2a)2(−b)+2(2a)(−b)2
Suitable identities isx3−y3−3x2y+3xy2=(x−y)3
∴(2a)3+(−b)3+3(2a)2(−b)+2(2a)(−b)2
=(2a−b)3
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