Math, asked by npavithra33, 3 months ago

factorise the following 121b²+88bc+16c²

Answers

Answered by Anonymous

0

Step-by-step explanation:

$121 {b}^{2} + 88bc + 16 {c}^{2} \\ (11b + 4c) {}^{2}$

I hope it helps you

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