Math, asked by abinmonachan2008, 1 year ago

factorise the following ​

Attachments:

Answers

Answered by ANTARYAMI247
1

Answer:

(4b-3c)^2-(3b+2c)^2

=(16b^2+9c^2-24bc)-(9b^2+4c^2+12bc)

=16b^2+9c^2-24bc-9b^2-4c^2-12bc

=7b^2+5c^2-36bc

if correct mark as brainliest

Similar questions