Factorise the following
14a2 + 11ab – 15b2
Answers
Step-by-step explanation:
Simplifying
14a2 + 11ab + -15b2 = 0
Reorder the terms:
11ab + 14a2 + -15b2 = 0
Solving
11ab + 14a2 + -15b2 = 0
Solving for variable 'a'.
Factor a trinomial.
(7a + -5b)(2a + 3b) = 0
Subproblem 1
Set the factor '(7a + -5b)' equal to zero and attempt to solve:
Simplifying
7a + -5b = 0
Solving
7a + -5b = 0
Move all terms containing a to the left, all other terms to the right.
Add '5b' to each side of the equation.
7a + -5b + 5b = 0 + 5b
Combine like terms: -5b + 5b = 0
7a + 0 = 0 + 5b
7a = 0 + 5b
Remove the zero:
7a = 5b
Divide each side by '7'.
a = 0.7142857143b
Simplifying
a = 0.7142857143b
Subproblem 2
Set the factor '(2a + 3b)' equal to zero and attempt to solve:
Simplifying
2a + 3b = 0
Solving
2a + 3b = 0
Move all terms containing a to the left, all other terms to the right.
Add '-3b' to each side of the equation.
2a + 3b + -3b = 0 + -3b
Combine like terms: 3b + -3b = 0
2a + 0 = 0 + -3b
2a = 0 + -3b
Remove the zero:
2a = -3b
Divide each side by '2'.
a = -1.5b
Simplifying
a = -1.5b
Solution
a = {0.7142857143b, -1.5b}
Step-by-step explanation:
the product of first and third terms equal to
21ab + 10ab this can be written
Hence, 14 a square + 11 a b - 15 b square
14a² -21ab -10ab-15b²
7ab(2a+3b) - 5b(2a+3b)
(2a+3b) ( 7a-5b)
I HOPE THIS WOULD help you (^.^)