factorise the following 16p^3-4p
Answers
Answered by
24
16p^3-4p=0
4p(p^2-1)=0
p^2-1=0
p^2=1
p=root(1)
p=1 is answer
4p(p^2-1)=0
p^2-1=0
p^2=1
p=root(1)
p=1 is answer
Answered by
50
HEYA MATE, HERE IS UR ANSWER ____________________________
16p^3-4p
=4p (4p^2-1)
= 4p {(2p)^2-(1)^2}
=4p (2p+1)(2p-1)
using identity a^2-b^2=(a+b)(a-b)
___________☆☆HOPE THE ANSWER HELPS YOU. ☆☆______☆☆BE BRAINLY ☆☆_______☆☆
16p^3-4p
=4p (4p^2-1)
= 4p {(2p)^2-(1)^2}
=4p (2p+1)(2p-1)
using identity a^2-b^2=(a+b)(a-b)
___________☆☆HOPE THE ANSWER HELPS YOU. ☆☆______☆☆BE BRAINLY ☆☆_______☆☆
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