factorise the following 1st 7x^2-7 2nd 8-50y^2z^2....
Answers
Answered by
8
1) 7x^2-7
take 7 as common
= 7(x^2-1)
now use the formula of (a^2-b^2)
= (a+b)(a-b)
= 7(x+1)(x-1)
therefore
x= -1, +1
2) 8- 50y^2z^2
taking out 2 common
= 2(4-25y^2z^2)
it can be written as
= 2(2^2-(5yz)^2)
now using formula of (a^2-b^2)
= (a+b)(a-b)
= 2(2-5yz)(2+5yz)
therefore
yz= 2/5, -2/5
take 7 as common
= 7(x^2-1)
now use the formula of (a^2-b^2)
= (a+b)(a-b)
= 7(x+1)(x-1)
therefore
x= -1, +1
2) 8- 50y^2z^2
taking out 2 common
= 2(4-25y^2z^2)
it can be written as
= 2(2^2-(5yz)^2)
now using formula of (a^2-b^2)
= (a+b)(a-b)
= 2(2-5yz)(2+5yz)
therefore
yz= 2/5, -2/5
Similar questions