factorise the following 2 x ki power 4 minus 128 x
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Q . Factorize 2x⁴ - 128x.
= 2x⁴ - 128x
By takinh 2x common,
= 2x ( x³ - 64 )
= 2x { (x)³ - (4)³ }
Using identity [ a³ - b³ = ( a - b ) ( a² + b² + ab ) ].
= 2x ( x - 4 ) { (x)² + (4)² + 4x }
= 2x ( x - 4 ) ( x² + 16 + 4x ).
= 2x⁴ - 128x
By takinh 2x common,
= 2x ( x³ - 64 )
= 2x { (x)³ - (4)³ }
Using identity [ a³ - b³ = ( a - b ) ( a² + b² + ab ) ].
= 2x ( x - 4 ) { (x)² + (4)² + 4x }
= 2x ( x - 4 ) ( x² + 16 + 4x ).
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Hey......this is your answer
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