Question

factorise the following : 216 ( a + b ) ^3 + 27​

Answer 1

Step-by-step explanation:

216 ( a + b ) ^3 + 27

formula (a+b)^3= a^3+b^3+3ab(a+b)

=216[a^3+b^3+3ab(a+b)] +27

=216 a^3+216b^3+216{3ab(a+b)}+27

=216a^3+216b^3+ 648ab(a+b)+27

= 216a^3+216b^3+648a^2b+648ab^2+27