Question

FACTORISE THE FOLLOWING 22. b2-6b-7 23. b2+5b+6 24. b2+5b-6 25. b2+18b+81

Answer 1

Step-by-step explanation:

we have to factorise it be splitting into 2 terms

${b}^{2} - 6b - 7$

we have to split 6b as its multiplication will be multiplication of 1st and 3rd number.

${b}^{2} - 7b + b - 7$

now we have to write common factor of 1,3 and 2,4 respectively {larger number should be in 2nd place}

$b(b + 1) - 7(b + 1)$

now write the term and common factor as follows

$(b - 7)(b + 1)$

now doing the next question by same procedure

${b}^{2} + 5b + 6$

${b}^{2} + 6b - b + 6$

$b(b - 1) - 6(b - 1)$

$(b - 1)(b - 6)$