Math, asked by Pragatiprakash, 7 months ago

Factorise the following ​

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Answered by BeautifullMind
5

Answer:

2m {}^{2} - 2n {}^{2} + 4mn - mn \\ = 2m {}^{2} - mn - 2n {}^{2} + 4mn \\ = m(2m - n) + 2n( - n + 2m \\ = m(2m - n) + 2n(2m - n) \\ = (m + 2n)(2m - n) \\ answer

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Answered by Ayushiashok2
3

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