factorise the following 25 x square + 4 y square + 9square -20 X Y + 12 Y Z - 30 x z
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Answer:
( - 5x + 2y + 3z)²
Step-by-step explanation:
25x² + 4y² + 9z² - 20xy + 12yz - 30xz
Note: Whenever three perfect squares and 6 terms are given, just consider the identity
a² + b² + c² + 2ab + 2bc + 2ca
Here, given expression can be written as
(5x)² + (2y)² + (3z)² - 2(5x)(2y) + 2(2y)(3z) - 2(3z)(5x)
If you'll compare last three term with last three terms of the identity, you'll observe that terms 2ab and 2ca are negative ( - 20xy and - 30xz) , in both of these terms (x) is common, so we can say coefficient of x is negative hence
(-5x)² + (2y)² + (3z)² + 2(-5x)(2y) + 2(2y)(3z) + 2(3z)(-5x)
= ( - 5x + 2y + 3z)² [∵a² + b² + c² + 2ab + 2bc + 2ca = (a + b + c)² ]
sambuzz:
Thanks
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