Math, asked by saniamalik29, 1 year ago

factorise the following
27 - 125a^3 - 135a + 225a^2​

Answers

Answered by bruce781
7

ANSWER=( 3-5a )^3

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Answered by riyagshah07
0

Answer:

(3-5a)^3

Step-by-step explanation:

First, write the above polynomial as

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get,

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)We have written 3^3 by 27

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)We have written 3^3 by 27So, therefore

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)We have written 3^3 by 27So, therefore (3-5a)^3

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)We have written 3^3 by 27So, therefore (3-5a)^3 Is our answer

First, write the above polynomial as125a^3 + 225a^2 - 135a + 27By using (a-b)^3 = a^3 - b^3 - 3ab (a-b)We get, -125a^3 + 3^3 - (3×3×5a) (3-5a)We have written 3^3 by 27So, therefore (3-5a)^3 Is our answerThank you !!!

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