Question

factorise the following 27 x cube - 8 y cube

Answer 1

$27 {x}^{3} - 8 {y}^{3}$
${(3x)}^{3} - {(2y)}^{3}$
Using
${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + {b}^{2} + ab)$
$(3x - 2y)(9 {x}^{2} + 4 {y}^{2} + 6xy)$
This is the factorised form.