Factorise the following:
(2a + b)^3 + (a + 2b)^3
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Required Answer:-
Given To Factorise:
- (2a + b)³ + (a + 2b)³
Solution:
We know that,
→ x³ + y³ = (x + y)(x² - xy + y²)
So, if x = 2a + b and y = 2b + a, then,
x³ + y³
= (x + y)(x² - xy + y²)
Substituting the values, we get,
= [(2a + b) + (2b + a)][(2a + b)² - (2a + b)(2b + a) + (2b + a)²]
= [3a + 3b][ (4a² + 4ab + b²) - {2a(2b + a) + b(2b + a)} + (4b² + 4ab + a²)]
= (3a + 3b)[(5a² + 5b² + 8ab) - (4ab + 2a² + 2b² + ab)]
= (3a + 3b)[5a² + 5b² + 8ab - 2a² - 2b² - 5ab]
= 3(a + b)(3a² + 3b² + 3ab)
= 3(a + b) × 3(a² + ab + b²)
= 9(a + b)(a² + ab + b)²
→ Therefore, the factorised form is 9(a + b)(a² + ab + b²)
Answer:
- The factorised form is 9(a + b)(a² + ab + b²)
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