factorise the following 2ab-6ac with proper steps
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Answered by
3
Step-by-step explanation:
Divide each one by two since two is common to all
2ab÷2- 6ac÷2
= ab - 3ac
Then take common factor 'a' out it will give u
= b-3c
Answered by
6
2ab - 6ac
= 2 x a x b - 2 x 3 x a x c
= 2 x a x (b - 3c)
= 2a(b - 3c)
= 2 x a x b - 2 x 3 x a x c
= 2 x a x (b - 3c)
= 2a(b - 3c)
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