Question

Factorise the following
(2m+3n)^2-(3m+2n)^2

Answer 1

HOLA..!!

(2m + 3n)² - (3m + 2n)²

= (2m + 3n + 3m + 2n) [ 2m + 3n - (3m + 2n)]

= (5m + 5n)(-m + n)

= -5(m + n)(m - n)

HOPE IT'LL HELP...:)

Answer 2

(2m + 3n)² - (3m + 2n)² = - 5(m + n)(m - n)

Given :

The expression (2m + 3n)² - (3m + 2n)²

To find :

To factorise the expression

Formula :

a² - b² = ( a + b ) ( a - b )

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

(2m + 3n)² - (3m + 2n)²

Step 2 of 2 :

Factorise the expression

(2m + 3n)² - (3m + 2n)²

$\sf = (2m + 3n + 3m + 2n)(2m + 3n - 3m - 2n)$

$\sf = (5m + 5n)( - m + n)$

$\sf = - (5m + 5n)( m - n)$

$\sf = - 5(m + n)( m - n)$

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