Question

factorise the following [2x+1/3] square -[x-1/2] square

please don't type hggjjk like this answer fair with steps​

Answer 1

Step-by-step explanation:

(2x + 1/3)^2 - (x-1/2)^2

using identity a^2 - b^2 = (a+b)(a-b)

here a = 2x + 1/3

b = x -1/2

so we get

(2x + 1/3)^2 - (x-1/2)^2 = (2x + 1/3 + x -1/2)(2x +1/3 - x +1/2)

(3x - 1/6)(x + 5/6)

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Answer 2

Answer:

[3x-1/6] [x+5/6]

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