factorise the following 2x^2+3√5x+5
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Answer:
Given, 2x2 + 3√5x + 5
= 2x2 + (2√5 + √5)x + √5*√5
= 2x2 + 2√5x + √5x + √5*√5
= 2x(x + √5) + √5(x + √5)
= (x + √5)*(2x + √5)
So, 2x2 + 3√5x + 5 = (x + √5)*(2x + √5)
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Given, 2x2 + 3√5x + 5
= 2x2 + (2√5 + √5)x + √5*√5
= 2x2 + 2√5x + √5x + √5*√5
= 2x(x + √5) + √5(x + √5)
= (x + √5)*(2x + √5)
So, 2x2 + 3√5x + 5 = (x + √5)*(2x + √5)
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