Question

Factorise the following .

2x(2a +3b) + 3y(2a +3b) – 4z(2a +3b).
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Answer 1

Answer:

2x(2a +3b) + 3y(2a +3b) – 4z(2a +3b).

(2a+3b)(2x+3y-4z)

Answer 2

Answer:

We can  see that (2a+3b) is common

So, we assume (2a+3b) as 'o'

Now

2xo+3yo-4zo

So we get

o (2x+3y-4z)

So replacing o, we get

(2a+3b)(2x+3y-4z)

Hope this helps u :)