Question

factorise the following 2x+4y-8xy-1​

Answer 1

Given : 2x+4y−8xy−1

we can futher write it as

2x+4y−8xy−1=2x−1−8xy+4y

By taking commen term out

2x+4y−8xy−1=(2x−1)−4y(2x−1)

So we get,

2x+4y−8xy−1=(2x−1)(1−4y)