Question

factorise the following
2yz-x(x-2y+z)​

Answer 1

Answer:

=2yz- (x²-2xy +xz)

=(2yz-x²+2×y-xz)

=2y(z+x)-x(z+x)

=(z+x)(2y-x).

Answer 2

$\huge\underline\purple{\sf SOLUTION :-}$

GIVEN EQUATION :-

2yz - x ( x - 2y + z )

On factorizing we get,

$= 2yz - {x}^{2} + 2xy - xz$

$= 2yz + 2xy - {x}^{2} - xz$

on taking common...

$= 2y(z + x) - x(x + z)$

$= (2y - x)(x + z)$

Which is required factorization.