Question

factorise the following ​

Answer 1

Answer:

q²-7q-3q+21

q(q-7)-3(q-7)

(q-3)(q-7)

q=7 and q=3

could you give some thanks

Answer 2

$\huge\bf{Answer :}$

Given in the attachment. ( Please rotate the image .)

$\huge\bf{Extra\: Information :}$

• There are many ways for factorising or finding roots of a particular equation. Some of them includes the method of prime factorisation, by completing the square method or by quadratic formula by finding the suitable discriminant.
• We factorise a particular equation for making our calculations easier and for finding the factors of that equation.
• The standard form of a quadratic equation : ax²+bx+y=c where, a = coefficient of x², b = coefficient of x and c = constant term. Here, a is never a zero. ( Reason - If a is zero, then x² would also get converted into zero and the given equation will be changed into a linear equation and the quadratic equation would not exist. )
• The quadratic equations have at most 2 zeroes.
• Basically, the zeroes of a quadratic polynomial p(x) are the co-ordinates that lies on the x-axis, where the graph of the equation, y=p(x) cuts the x-axis.
• There are several methods for finding the unknown values of x and y in a liner equations. Some of them are Elimination method, Cross-multiplication method, and substitution method.
• A quadratic equation in the form of ax²+bx+c=0 has, 1) No real roots, provided the condition that b²-4ac<0, 2) Two equal roots( or coincident roots ), provided the condition that b²-4ac=0 , and 3) Two distinct roots, provided the conditions that b²-4ac>0.