Question

factorise the following 3x^5-48^3

Answer 1

HEYA MATE, HERE IS UR ANSWER __________________________

3x^5-48^3
=3x^3 (x^2-16)
= 3x^3 {(x)^2-(4)^2}
using identity a^2-b^2=(a+b)(a-b)
=3x^3 (x+4)(x-4)

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Answer 2

✌✌HERE IS YOUR ANSWER..⬇⬇

$\green{\underline{SOLUTION}}$ ➡

$3x {}^{5} - 48 {}^{3} \\ \\ = 3 {}^{3} (x {}^{2} - 16) \\ \\ = 27(x {}^{2} - 4 {}^{2} ) \\ \\ = 27(x + 4)(x - 4)$


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