factorise the following
(3x+5y)^2-4z^2
Answers
Answered by
57
Here, we are given two terms :-
(3x + 5y)² and 4z²
4z² = (2z)²
Now, we can use the identity
a² - b² = (a + b)(a - b)
Taking (3x + 5y) as a² and (2z)² as b² we get
(3x + 5y)² - 4z²
= (3x + 5y)² - (2z)²
= (3x + 5y + 2z)(3x + 5y - 2z)
Hence, your answer is
(3x + 5y + 2z)(3x + 5y - 2z)
(3x + 5y)² and 4z²
4z² = (2z)²
Now, we can use the identity
a² - b² = (a + b)(a - b)
Taking (3x + 5y) as a² and (2z)² as b² we get
(3x + 5y)² - 4z²
= (3x + 5y)² - (2z)²
= (3x + 5y + 2z)(3x + 5y - 2z)
Hence, your answer is
(3x + 5y + 2z)(3x + 5y - 2z)
Answered by
13
hello here Is your answer OK
3x+5y2-4z2=3x+5y2- 2z2=3x + 5y + 2z3x + 5y - 2z
OK
3x+5y2-4z2=3x+5y2- 2z2=3x + 5y + 2z3x + 5y - 2z
OK
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