Question

factorise the following​

Answer 1

Answer:

answer 1)(x+1)(x-1)(x-2)

answer 2)(y+1)(y-1)(2y+1)

Answer 2

Step-by-step explanation:

x^3-2x^2-x+2

=x^3-x-2x^2+2

=x(x^2-1)-2(x^2-1)

=( x^2-1) (x-2)

=[x^2-(1)^2] (x-2)

=(x+1)(x-1)(x-2)

2y^3+y^2-2y-1

=y^2(2y+1)-1(2y+1)

=(2y+1) (y^2-1)

=(2y+1)[y^2-(1)^2]

=(2y+1)(y+1)(y-1)

Hope this helps you.