Factorise the following.
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Given :-
81x⁴ - (1/81x⁴)
To find :-
The factorisation of the expression
Solution :-
Given expression is 81x⁴ - (1/81x⁴)
=> 9²(x²)² - [1/{9²(x²)²}]
=> (9x²)²-(1/(9x²)²
It is in the form of (a+b)(a-b)
Where a = 9x² and b = (1/9x²)
We know that
(a+b)(a-b) = a²-b²
=> [9x²+(1/9x²)][9x²-(1/9x²)]
=> [9x²+(1/9x²)][(3x)²-(1/3x)²]
[(3x)²-(1/3x)²] is in the form of (a+b)(a-b)
Where a = 3x and b = (1/3x)
We know that
(a+b)(a-b) = a²-b²
=> [9x²+(1/9x²)][3x+(1/3x)][3x-(1/3x)]
Answer :-
81x⁴-(1/81x⁴)=[9x²+(1/9x²)][3x+(1/3x)][3x-(1/3x)]
Used formulae:-
♦ (a+b)(a-b) = a²-b²
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1
Answer:
Hope this will help u
Step-by-step explanation:
By using identity (a^2-b^2) we can solve this.
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