Math, asked by Toshita311, 1 year ago

Factorise the following
4a^2-25b^2+30b-9

Answers

Answered by MaheswariS
1

\textbf{Given:}

\mathsf{4a^2-25b^2+30b-9}

\textbf{To factorise:}

\mathsf{4a^2-25b^2+30b-9}

\textbf{Solution:}

\textbf{Identity used:}

\boxed{\begin{minipage}{5cm}$\\\mathsf{1.\;\;(a-b)^2=a^2-2ab+b^2}\\\\\mathsf{2.\;\;a^2-b^2=(a-b)\;(a+b)}\\$\end{minipage}}

\mathsf{Consider,}

\mathsf{4a^2-25b^2+30b-9}

\mathsf{=4a^2-(25b^2-30b+9)}

\mathsf{=4a^2-((5b)^2-2{\times}5b{\times}3+3^2)}

\textsf{Using identity (1),}

\mathsf{=4a^2-(5b-3)^2}

\mathsf{=(2a)^2-(5b-3)^2}

\textsf{Using identity (2),}

\mathsf{=(2a-(5b-3))\,(2a+5b-3)}

\mathsf{=(2a-5b+3)\,(2a+5b-3)}

\implies\boxed{\mathsf{4a^2-25b^2+30b-9=(2a-5b+3)\,(2a+5b-3)}}

\textbf{Find more:}

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