Question

factorise the following 4a^2-9

Answer 1

©4a^2 - 9



= ( 2a )^2 - ( 3 ) ^2





=( 2a - 3 ) ( 2a + 3 )

Answer 2

we may write (4a^2-9) in the form of (a^2-b^2)

so, (2a)^2- (3)^2

(a^2-b^2)= (a+b) (a-b)

(2a+3) (2a-3)