Question

factorise the following 4a2b-9b3​

Answer 1

$hope \: it \: helps \: you \: ..$

Answer 2

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4a²b - 9b³

= b( 4a² - 9b³)

= b[ (2a)² - (3b)² ]

= b( 2a - 3b )( 2a + 3b ) [ a2 - b2 = (a+b) (a-b) ]

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