Math, asked by mariyamkundawala9339, 6 months ago

factorise the following 4x^4+ 8x^2+ 9
plz help me ​

Answers

Answered by XxMasterMindxX
5

256X⁴+64x²+9

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Answered by saksham1312
1

Answer:

Simplifying

4x4 + 8x2 + 9 = 0

Reorder the terms:

9 + 8x2 + 4x4 = 0

Solving

9 + 8x2 + 4x4 = 0

Solving for variable 'x'.

Begin completing the square. Divide all terms by

4 the coefficient of the squared term:

Divide each side by '4'.

2.25 + 2x2 + x4 = 0

Move the constant term to the right:

Add '-2.25' to each side of the equation.

2.25 + 2x2 + -2.25 + x4 = 0 + -2.25

Reorder the terms:

2.25 + -2.25 + 2x2 + x4 = 0 + -2.25

Combine like terms: 2.25 + -2.25 = 0.00

0.00 + 2x2 + x4 = 0 + -2.25

2x2 + x4 = 0 + -2.25

Combine like terms: 0 + -2.25 = -2.25

2x2 + x4 = -2.25

The x term is 2x2. Take half its coefficient (1).

Square it (1) and add it to both sides.

Add '1' to each side of the equation.

2x2 + 1 + x4 = -2.25 + 1

Reorder the terms:

1 + 2x2 + x4 = -2.25 + 1

Combine like terms: -2.25 + 1 = -1.25

1 + 2x2 + x4 = -1.25

Factor a perfect square on the left side:

(x2 + 1)(x2 + 1) = -1.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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