Question

factorise the following 4x2+9y2+16z2+12xy+24yz+16xz

Answer 1

(2x)^2+(3y)^2+(4z)^2+2 (2x )(3y)+ 2 (3y)(4z) +2 (4z)(2x)

=(2x+3y+4z)^2

=(2x+3y+4z)(2x+3y+4z) (Ans)

Hope it helps!!!

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Answer 2

$4x {}^{2} + 9x {}^{2} + 16z {}^{2} + 12xy + 24yz + 16xz \\ \\ = (2x ) {}^{2} + (3y) {}^{2} + (4z) {}^{2} + 2 \times 2x \times 3y + 2 \times 3y \times 4z + 2 \times 4z \times 2x \\ = (2x + 3y + 4z) {}^{2}$