Question

☆☆☆factorise the following☆☆☆

Answer 1

$\mathf { p^2 - \dfrac{1}{10} p - \dfrac{3}{10} }$

Take out common term 1/10:

$\mathf { \dfrac{1}{10} (10 p^2 - p - 3) }$

Factorise:

$\mathf { \dfrac{1}{10} (5p - 3) (2p + 1) }$

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$\mathf { -\dfrac{3}{2}a^4 + 3a^2b^2 -\dfrac{3}{2}b^4 }$

Take out common factor -1/2:

$\mathf { -\dfrac{3}{2} (a^4 - a^2b^2+3b^4) }$

Group them into a² - 2ab + b²:

$\mathf { -\dfrac{3}{2} [(a^2)^2 -(2(ab)^2+(b^2)^2] }$

Factorise the perfect square : (a² - 2ab + b²) = (a - b)²:

$\mathf { -\dfrac{3}{2} (a^2 - b^2)^2}$

Factorise the difference of perfect square: (a² - b²) = (a + b)(a - b):

$\mathf { -\dfrac{3}{2} [ (a + b)(a - b)] ^2}$

Answer 2

Answer:

Take out common term 1/10:

Factorise:

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Take out common factor -1/2:

Group them into a² - 2ab + b²:

Factorise the perfect square : (a² - 2ab + b²) = (a - b)²:

Factorise the difference of perfect square: (a² - b²) = (a + b)(a - b):