Question

Factorise the following :64 - (a+1)²​

Answer 1

$64 - {(a + 1)}^{2}$

$64 - ( {a}^{2} + 1 + 2a)$

$- {a}^{2} - 1 - 2a + 64 = 0$

${a}^{2} + 2a + 1 - 64 = 0$

${a}^{2} + 2a - 63 = 0$

${a}^{2} + 9a - 7a - 63 = 0$

$a(a + 9) - 7(a + 9)$

(a-7) (a+9)

a = 7 , a = -9 Ans.