factorise the following:
64a3–27b3–144a2b+108ab2
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Answered by
8
Answer:
(4a-3b)(4a-3b)(4a-3b)
Step-by-step explanation:
64a3-27b3-144a2*+108ab2
64a3-27b3-144a2v+108ab2
(4a)3-(3b)3-3(4a)(3b)(4a-3b)
(4a-3b)3 using identity VII
(4a-3b)(4a-3b)(4a-3b)
Answered by
6
Step-by-step explanation:
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