Question

factorise the following 64m^4 - 125n3​

Answer 1

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We have 64m³ −343n ³ =(4m) ³−(7n)³

Using x³ −y ³=(x−y)(x ²+xy+y²)

☞ (4m−7n){(4m)² +(4m)(7n)+(7n)²}

=(4m−7n)(16m² +28)mn

Answer 2

Step-by-step explanation:

Given Polynomial: 64m3 – 343n3

64m3 – 343n3 = (4m)3 – (7n)3.

Now, by using the formula, x3 – y3 = (x-y)(x2 +xy+y2),

we can write the given expression as:

= (4m-7n)[(4m)2+(4m)(7n)+ (7n)2]

= (4m -7n)(16m2+28mn+49n2)

Therefore, 64m3 – 343n3 = (4m -7n)(16m2+28mn+49n2)