Question

factorise the following 7 a square + 14 a b + 7 b square​

Answer 1

Answer:

7(asquare+2ab+bsquare)=0

asquare+2ab+bsquare=0

(a+b)^2

Answer 2

Answer:

The factors are $(\sqrt{7}a+\sqrt{7}b)^{2}$.

Step-by-step explanation:

The expression is: $7a^{2}+14ab+7b^{2}$

The expansion of (a + b)² is: $(a+b)^{2}=a^{2}+2ab+b^{2}$

Use the above expansion to factorize the expression as follows:

$7a^{2}+14ab+7b^{2}=(\sqrt{7}a)^{2}+(2\times\sqrt{7}a\times \sqrt{7}b)+(\sqrt{7}b)^{2}=(\sqrt{7}a+\sqrt{7}b)^{2}$

Thus, the factors are $(\sqrt{7}a+\sqrt{7}b)^{2}$.