factorise the following
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✌️✌️hey mate here is the answer...
➡️y²-7y+12=0
➡️y²-3y-4y+12=0
➡️y(y-3)-4(y-3)=0
➡️(y-3)(y-4)=0
➡️y-3=0 or y-4=0
➡️y=3 or y=4
thanks...
nice to help you ✌️✌️
➡️y²-7y+12=0
➡️y²-3y-4y+12=0
➡️y(y-3)-4(y-3)=0
➡️(y-3)(y-4)=0
➡️y-3=0 or y-4=0
➡️y=3 or y=4
thanks...
nice to help you ✌️✌️
Answered by
0
y²-7y+12,
(y-3) (y-4)
(y-3) (y-4)
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