factorise the following 9a^2-b^2+4b-4
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according to the question...
9a^2 - ( b^2 - 4b + 4 )
9a^2 - ( b^2 - 2b - 2b + 4 )
9a^2 - ( (b-2)(b-2) )
(9a)(a) - ( (b-2)(b-2) )...
9a^2 - ( b^2 - 4b + 4 )
9a^2 - ( b^2 - 2b - 2b + 4 )
9a^2 - ( (b-2)(b-2) )
(9a)(a) - ( (b-2)(b-2) )...
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9ᴀ^2 - ʙ^2 + 4ʙ - 4
= 9ᴀ^2 - { ( ʙ)^2 - 2 × ʙ × 2 + ( 2 )^2 }
= ( 3ᴀ )^2 - ( ʙ - 2 )^2
= ( 3ᴀ + ʙ - 2 ) ( 3ᴀ - ʙ + 2 )
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9ᴀ^2 - ʙ^2 + 4ʙ - 4
= 9ᴀ^2 - { ( ʙ)^2 - 2 × ʙ × 2 + ( 2 )^2 }
= ( 3ᴀ )^2 - ( ʙ - 2 )^2
= ( 3ᴀ + ʙ - 2 ) ( 3ᴀ - ʙ + 2 )
_____________________
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