Question

factorise the following a^2+8a+16

Answer 1

a²+ 8a+ 16
= a²+ 4a+4a+16
= a(a+4) +4(a+4)
= (a+4)(a+4)
= (a+4)²

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Answer 2

Factorise: $a^{2} +8a+16$

Solution:

$:\implies a^{2} + 2 \times 4 \times a+ 4^{2} \\:\implies (a+4)^{2}$

Using Identity = $(x+4)^{2} = x^{2} + 2xy + y^{2}$