Math, asked by sancta2006, 5 months ago

factorise the following
a^6-64​

Answers

Answered by asahilthakur
1

Answer:

(a³-8)(a³+8)

Step-by-step explanation:

a⁶ - 64

= a⁶ - (2)⁶

= [(a)³]² - [(2)³]²

= (a³-2³)(a³+2³)

= (a³-8)(a³+8)

Answered by kritikatiwari884
0

Answer:

Step-by-step explanation:

a^6 - 64

= a^6 - 2^6

= (a^3)^2 - (2^3)^2

= (a^3 - 2^3) (a^3+2^3)

use this identity to solve further

a³ - b³ = ( a - b) ( a² + ab + b² )

a³ + b³ = ( a + b) (a² - ab + b² )

hope it helps u.

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