Question

FACTORISE THE FOLLOWING
(A) 9X²—12XY+4Y²
(B) 25a²+60ab+36b²
(C) 49p²—112Pq+64q²

Answer 1

A-9x^2-12xy+4y^2

This is the identity

(a+b)^2=a^2-2ab+b^2

=(3x^2)-2.3x.2y-(2y)^2

=(3x-2y)^2

=(3x-2y) (3x-2y)

Answer 2

$1)9 {x}^{2} - 12xy + 4 {y}^{2} \\ = > ( {3x})^{2} - 2 \times 3x \times 2y + ( {2y})^{2} \\ = > ( {3x - 2y})^{2}\\=>(3x-2y)(3x-2y) \\ 2) 25 {a}^{2} + 60ab + 36 {b}^{2} \\ = > ( {5a})^{2} + 2 \times 5a \times 6b + ( {6b})^{2} \\ = >( {5a + 6b})^{2} \\=>(5a+6b)(5a+6b)\\ 3)49 {p}^{2} - 112pq + 64 {q}^{2} \\ = > ( {7p})^{2} - 2 \times 7p \times 8q + ( {8q})^{2} \\ = > ( {7p - 6q})^{2}\\=>(7p-6q)(7p-6q)$

hope this helps.

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