Factorise the following a(a+b+c) – bc.
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Step-by-step explanation:
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Given : a(a+b−c)−bc
We can further write it as
a(a+b−c)−bc=a
2
+ab−ac−bc
By taking the common terms out
a(a+b−c)−bc=a(a+b)−c(a+b)
So we get,
a(a+b−c)−bc =(a+b)(a−c)
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