factorise the following (a + b + c) 2 minus (a minus b minus C) 2
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Step-by-step explanation:
(a+b+c)²-(a-b-c)²= (a+b+c-a+b+c)(a+b+c+a-b-c)
= (2b+2c)(2a)=4a(b+c)
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