factorise the following a cube + 3 a square + b + 3 a b square + 2 b cube
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a3 + 3a2b + 3ab2 + b3 - 8
= a3 + b3 + 3ab (a + b) - 8
= (a + b)3 - (2)3 [Using identity]
= (a + b - 2) [(a + b)2 + 2(a + b) + 4] [Using identity]
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