Question

factorise the following a quadratic polynomial by splitting the middle term ​

Answer 1

${y}^{2} + 7y - 8$

${y}^{2} - 1y + 8y - 8 \\ y(y - 1) + 8(y - 1) \\ (y + 8)(y - 1) = 0 \\ y = - 8 \\ y = 1$

$\boxed{y=-8,y=1}$

Answer 2

Hope it will be help


Radhe Radhe